Given below is the plot of a potential energy function U(x)…

Physics Work, Energy, Power and Collision JEE Main 2021 MCQ (Single Correct)

Given below is the plot of a potential energy function U(x) for a system, in which a particle is in one dimensional motion, while a conservative force F(x) acts on it. Suppose that E mech =8J, the incorrect statement for this system is:

at x>x 4 , K.E. is constant throughout the region.

at x<x 1 , K.E. is smallest and the particle is moving at the slowest speed.

at x=x 2 , K.E is greatest and the particle is moving at the fastest speed.

at x=x 3 , K.E.=4J

Text Solution

Verified by Experts

The correct answer is:

E mech =8J

at x > x 4 , U = constant = 6 J

K = E mech − U = 2 J = constant

at x < x 1 , U = constant = 8 J

K = E mech. − U = 8 − 8 = 0 J

Particle is at rest.

At x = x 2 , U = 0 ⇒ E mech. = K = 8 J

KE is greatest, and particle is moving at fastest speed.

x = x 3 , U = 4 J

At U + K = 8 J

K = 4 J

Prepare Smarter with CGP Edu

Get practice questions, solutions, and test series in one place.

Write a Review

Share your experience with this question and solution.

Commentary

Send your comment, doubt, correction, or feedback to admin.

Student Reviews

What students say about this solution

No reviews yet. Be the first to write a review.

Share this question

Text Solution

Prepare Smarter with CGP Edu

Write a Review

Commentary

Student Reviews

Similar Questions